(40/(x^2)-25)-(4/(x-5))=(6/(x+5))

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Solution for (40/(x^2)-25)-(4/(x-5))=(6/(x+5)) equation: 



(40/(x^2)-25)-(4/(x-5))=(6/(x+5))

We move all terms to the left:

(40/(x^2)-25)-(4/(x-5))-((6/(x+5)))=0



Domain of the equation: x^2-25)!=0

x∈R





Domain of the equation: (x-5))!=0

x∈R





Domain of the equation: (x+5)))!=0

x∈R



We get rid of parentheses

40/x^2-(4/(x-5))-((6/(x+5)))-25=0

We calculate fractions

We do not support expression: x^3

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